思路：单调递增栈 + k 控制删除次数。高位越小整体越小，遇更小数字时弹出栈顶大数（仅当 k0）；栈空且当前为 0 则跳过（避免前导零）；若遍历完 k 仍0，从末尾再删 k 位。
Author(s): Ilia Baliakin, Svetlana Rempel, Albina Valeeva, Xiaojun Han
。业内人士推荐同城约会作为进阶阅读
"There was a big step – jump – that people have questioned," Jackson says. "But now the world is awash with oil and it's not clear that the same calculations still apply."
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